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25k^2=60k-32
We move all terms to the left:
25k^2-(60k-32)=0
We get rid of parentheses
25k^2-60k+32=0
a = 25; b = -60; c = +32;
Δ = b2-4ac
Δ = -602-4·25·32
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-20}{2*25}=\frac{40}{50} =4/5 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+20}{2*25}=\frac{80}{50} =1+3/5 $
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